The performance of a nuclear power plant

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QUESTION: What is the yield of a nuclear plant?

ANSWER : the yield of a nuclear plant is of the order of 30%.

EXPLANATION: This means that 70% of the "atomic" energy from the fission of uranium 235 is "tempered" into heat in the cooling towers.

For a plant reactor 2 1,3 electric GW, this corresponds to a heat loss of about 6 GW and an atomic power 8,6 GW.

These 6 GWs are "evacuated" in the cooling towers of French power plants, there is one tower per reactor (you can therefore easily know the number of reactors in a power plant by counting the number of revolutions).

Heating requirements of a modern home are roughly (smoothed over the year) of 60 W by m2. Whether for a house m100 2, 6 kW.The "lost" thermal energy of a single power plant at 2 reactors therefore corresponds to the heating of one million houses!

Assuming (which is not the case but for the image) that was recovered as energy cogeneration 14 16 to nuclear reactors would be enough to heat the whole of France without any consumption of heating or electrical or fuel oil or gas!

More:
- Is nuclear cogeneration possible?
- France Map of nuclear power plants
- Map of nuclear power plants worldwide
- Forum of Nuclear Energy
- Followed by the nuclear accident in Japan following the earthquake of March 11 2011
- All your questions about nuclear energy in a nuclear expert
- The power of a nuclear reactor
- Nuclear and wind load factor

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1 comment on "The performance of a nuclear power plant"

  1. the number of "cooling towers" does not correspond to the number of reactors, eg the "Bugey"
    possede 4 reactors "REP of 900 MW"; two reactors (bugey 2 and 3) have no cooling towers and two 900 mw (bugey 4 and 5) rep reactors have two cooling towers per reactor; another example: the Tricastin plant, two cooling towers for
    4 reactors, therefore, no relationship between the "number of cooling towers / number of reactor".

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