The yield of a nuclear plant

Share this article with your friends:

QUESTION: What is the yield of a nuclear plant?

ANSWER : the yield of a nuclear plant is of the order of 30%.

EXPLANATION: This means that 70% of the energy "atomic" after the fission of uranium 235 is "wasted" heat in cooling towers.

For a plant reactor 2 1,3 electric GW, this corresponds to a heat loss of about 6 GW and an atomic power 8,6 GW.

These 6 GW are "evacuated" in the cooling towers of the French power stations, there is a tower with reactor (so you can easily know the number of reactors in a central counting the number of turns).

Heating requirements of a modern home are roughly (smoothed over the year) of 60 W by m2. Whether for a house m100 2, 6 kW.The thermal energy "lost" a single plant 2 reactors therefore corresponds to the heating of one million homes!

Assuming (which is not the case but for the image) that was recovered as energy cogeneration 14 16 to nuclear reactors would be enough to heat the whole of France without any consumption of heating or electrical or fuel oil or gas!


More:
- Is nuclear cogeneration possible?
- France Map of nuclear power plants
- Map of nuclear power plants worldwide
- Forum of Nuclear Energy
- Followed by the nuclear accident in Japan following the earthquake of March 11 2011
- All your questions about nuclear energy in a nuclear expert
- The power of a nuclear reactor
- Nuclear and wind load factor

Feedback

1 comment on "The performance of a nuclear power plant"

  1. The number of "cooling towers" does not correspond to the number of reactors, eg the "Bugey" power plant
    Possess 4 reactors "REP of 900 MW"; Two reactors (bugey 2 and 3) have no cooling towers and two 900 mw reactors (bugey 4 and 5) have two cooling towers per reactor; Another example: the Tricastin plant, two cooling towers for
    4 reactors, therefore, no ratio between the "number of cooling towers / number of reactor".

Leave a comment

Your email address will not be published. Required fields are marked with *