Perpetuum Mobile. Explanation.

[Mikhail]

The operating principles and calculations of an engine float 01 11357

We manufacture the float (of variable volume) in such a way that in the minimum volume state it weighs 10 kg UNDER WATER, and in the maximum volume state it weighs less than water (-) 10 kg, so that 'it emerges to the surface. For example, if its weight is = 110 kg, its volume is = 100 liters in its min. Volume state. and 120 liters in the maximum volume state.
The float is airtight, inside is the air and its mechanism, e.g .:

The mechanism includes the mass (any concrete mass, for example, or a volume filled with sand), which is fixed to the end of a lever arm. Inside are (or the) gas springs, and the piston. The gas spring is a cylinder with the piston, filled with nitrogen under pressure. Gas springs, e.g. are used in automobiles to hold the rear door (or hood), which opens from bottom to top.
The float is underwater, e.g. at a depth of 3 m, the piston turned upwards, as shown in the drawing:


We analyze that is happening:
The mass (for example of a weight = 100 kg) will move downwards, it will move (draw inside) the piston, reducing the volume of the float and compressing the gas springs (to which we store the 'potential energy).
At the depth of 3 m, the water pressure = 0,3 kg / cm². This pressure acts on the piston with force, proportional to the area of ​​the piston. If the area of ​​the piston = 800 cm², the water at the depth of 3 m will act on the piston by the force of: 800 * 0,3 = 240 kg. At the end of the lever arm there will be 240/2 = 120 kg. If the gas springs are at the end of the lever, on the springs we will have the weight of the mass (100 kg) and the force of 120 kg, coming from the piston. At the end of the lever arm we will have: 100 + 120 = 220 kg. We choose gas springs with a pushing force = 220 kg.

The float decreases its volume, its weight under water becomes = 10 kg and it rolls towards the bottom. Assume that the depth of the pissine is = 8 m. The float goes from the depth of 3 m to the depth of 8 m. Path traveled = 5 m.

Let us assume that the height of the float allows the mass to move at the distance = 50 cm.
The course of the mass = 50 cm. Since the piston is pushed through the middle of the lever, it will pass the distance 50/2 = 25 cm. The piston surface area = 800 cm² * 25 cm = 20 cm.cube = 000 liters. The displacement of the piston decreased the volume of the float to 20 liters.
For a weight of 110 kg and the volume (of the float underwater) of 100 liters, its weight (underwater) is = 10 kg. The 10 kg float "falls" from a height of 5 m (under the effect of gravity).
The float "fell" (sank) to the depth of 8 m. The mass inside the float is at the bottom, the piston is moved (is drawn) inside.

Now we return the float to 180 °. For this we must lift a weight of 10 kg at the height of 50 cm (the float weighs under water 10 kg, the mass is at the bottom) so that the mass passes over. The mass travels = 50 cm.
The float will be in this position:

Gravitation and gas springs (they will return the accumulated energy) will move the mass down, push the piston down (from inside to outside), having increased the volume of the float by 20 liters. Now the float is lighter than water, it weighs under water (-) 10 kg and will go up to the top, to the depth of 3 m, there we stop it.

The float, "falling" from the height of 5 m, produces energy and to turn it over, it is also necessary to expend energy. Ctd, the float (10 kg) "fell" from a height of 5 m and to turn it over, it must be lifted (its weight of 10 kg when turning it) to a height of 50 cm.
From here: 5 m - 0,5 m = 4,5 m - the distance over which the float produces energy.
Energy does not depend on the trajectory, but only on the height.
Above (at depth 3 m) you have to turn it over again, spending the same amount of energy as below, and it flows, etc.

So that the floats turn around themselves and to increase the system power, we fix the floats to a chain (or chains), which bypass the wheels and the floats turn around, bypassing the wheels.


The floats turn 180 ° up and 180 ° down, bypassing the wheels and they produce useful work (energy) by going down (flowing) and going up (by floating up).
That's all.

[Christophe]

Subject already widely discussed and debated ...