Mini hydraulic power plant

[Chatdumidi cat]

Hello,
just starting out in electronics I was wondering if it was possible to use the thrust of water at an average flow rate of 180L / h
in the evacuation pipe of a sink to have a constant production (the time of the flow) in order to feed a 2 watt appliance.

I hope my question is not too silly, thank you for your answer.

[highfly-addict]

So let's see:
Required power of the device:
2 W equivalent to 2 d / s.

Power available:
1 joule is the energy required to raise 100 g of 1 m.
By counting wide (friction, conversion losses, ...) we can therefore hope to recover within 6 joules per liter per meter (height of fall), as it is a sink, 6 d / l.

180 l / h is a small flow of 3 l / min, i.e. a recovered energy of 18 d / min or 18/60 = 0.3 d / s

Here, your flow is at least 6 times too small .... Sorry

edit: approximate reasoning, the reality is probably even more cruel!

[hic]

Hello,
just starting out in electronics I was wondering if it was possible to use the thrust of water at an average flow rate of 180L / h
in the evacuation pipe of a sink to have a constant production (the time of the flow) in order to feed a 2 watt appliance.

I hope my question is not too silly, thank you for your answer.

Hi chatdumidi

You are at 50mW on a meter (180Kg / 1m / 3600s)

[Chatdumidi cat]

Very well thank you for answering me, I saw a lot but as I told you I don't know much about it I hadn't thought that producing 2watt was so difficult.
Good day to you !