machine drum washing impeller

[coucou789456]

Good evening
it must be a synchronous motor, not easy to modify it, unless you remove part of the scrap from the rotor, to put magnets in it. a bicycle dynamo, no more than 6 to 10w: not great.
an alternator recovering for breakage should go but producing direct current is not ideal because it would still require gear to convert it to ad hoc voltage for current use (inverter) without forgetting the losses due to transformations.
there are alternators which give their nominal power at a slow rotation but the price should not correspond to what you expect.
for example in this pdf document on a wind turbine, generator at 240 rpm for its nominal power https://www.econologie.info/share/partag ... 6x6D5P.pdf

jeff

[nlc]

What's going to be the rotation speed in rpm Christophe? I may have an idea ...

[Christophe]

Ben Nlc, according to the measurements, 8 km / h of max current. Angular velocity of 7,33 Rad / s

In revolutions per second it does: 7,33 / 2 * Pi = 1,16 t / s or 70 in rpm.

This is the maximum speed. The average speed will probably be 30% less (the flow of the stream varying quite strongly).

[nlc]

Ah it's too low, I was thinking of an electric bicycle wheel motor as a generator. But 70rpm is too little

[Bibiphoque]

Hello,
With this low speed of rotation, you will need a reduction or find a generator with a very large number of poles.
@+

[Obelix]

Hello,

And why not use a simple wind turbine as a tidal turbine?
Mounted on a tripod with a handle, it is set up and removed easily!

Power: P = 1/2 d SV ^ 3
For 300W on the tree at 2m / s P = 1/2 x 1000 x S x 8 = 300
Let S = 300/4000 => 0.075 m²
To be correlated with the estimated yield anyway!
This represents a tidal turbine of 30cm by 70cm => 0.210 m² which with an efficiency of 30% gives 0.075 m²
We can do better (40% for lenz turbine)!
It remains to be seen how to recover the power because the reel does not turn quickly ........
For a vacuum Lenz turbine 1.66 at maximum load 0.8 of TSR, i.e. for the above conditions 204 revolutions / m vacuum and 102 revolutions / m at full load!


Obelix

[Christophe]

Ah it's too low, I was thinking of an electric bicycle wheel motor as a generator. But 70rpm is too little

Uh 70 it is without the reduction. I retrieved the crown drive belt (on the other side it is directly the motor axis).

Not with the wheel motor ... it's just the power I need ... Are you sure it is 100% reversible? That is to say that it can run at 100% of the engine power in generator?

By cons it's 12V .... well I'm not going to spit in the soup either

I'll take some pictures right away.

[nlc]

Yes, they are permanent magnet motors, 100% reversible.
And no it's not 12V, in fact like any permanent magnet motor / generator the voltage depends on its speed of rotation.

[Christophe]

Didn't know? So is there a regulator on the bikes?

What comes out precisely? (between how much and how many volts? In AC or DC? If AC how many Hz?).

Sorry am a bit of a sucker in this area ...

[nlc]

No regulator, it's just magnets that pass in front of the windings

A brushless motor will output you a three-phase AC voltage. The "Hz" depend on your speed of rotation and the number of poles, the volt / rpm coefficient depends on the motor (number of turns, magnet, etc.)

A brush motor will take out a DC voltage on 2 wires. The coef volt / rpm also depends on the motor.

In general under 36V at no load a wheel motor will make you turn the wheel at 25-30Km / h on 26 "