first we must pay attention to the different types Black 600 12v or 24V or 48V because the voltages produced vary according to the same report.
In your posts it is necessary to remember this tension to be sure that you have the same model, and to avoid possible confusion.
The values are probably the optimal operating values at mppt with maximum power given.
This mppt is that given by the wind to the wind turbine, which includes the power lost in the winding of the wind turbine is RxI ^ 2 which is not negligible, to see closely with the internal resistance, about R = 0,5 to 0,6 Ohms for that at V = 12V, 4 times more for model 24V and 8 times for that at 48V, as far as I guess the value if the total volume of copper wound remains constant.
With V multiplied by 2, I is divided by 2 and RI ^ 2 unchanged by R multiplied by 4 because it believes that the square
The 24V model is indicated as giving 12V to 1,8 at 2m / s of wind, without any vorticity, and therefore not at the top of an ordinary flag roof.
Another parameter is the speed of rotation which has the optimum must be proportional to that of the wind, more precisely, with the speed of the tip of the tapered blades, about 5 times that of the wind.
this is imposed by the blades to have the relative wind with the right incidence, without stalling (blade too slow) or negative impact which slows down, (blade too fast).
The vortices destroy the good incidence and the speed decreases to about that of the wind at least and the yield decreases of this factor 5 at least.
So this type of wind turbine with houses around, is often a scam as explained on the report:
https://www.econologie.com/forums/post242163.html#242163
http://www.youtube.com/watch?v=qLTCZMlgtJI
So the frequency of the generated current gives the speed of rotation which must be wedged to that of the wind for this optimum, with the obtained tension also proportional to this wind speed, about 30 to 35V for 10 to 11m / s of wind for the model 12V.
2tour / s = 120 per minute gives 10Hz as indicated in German, and for a diameter of 1,6m is 5m of circumference, we get 11m / s for max power 600W on paper sellers, 11m / sx5 / 5m = 11 turns / s is 55 Hertz which corresponds to a voltage of 29V on the 12V model, thanks to an indication of 24Hz for 12,6V in the forum German.which also allows to guess that the current flow is about 20 to 25 A (with the battery charge current of 12V function of this frequency).
The model 12V gives its max power to 30V for 600W = 30x20 and a little above, with at least I = 20 amps which gives the power lost in the coils of 0,6Ohmsx20x20 = 240W, or even more that quickly believes like the square of I .
And the alternator is going heat very strongly, even in this wind !!
So at 600W the wind actually delivers to the blades a mechanical energy of 600 + 250 = 850W
This power is obtained only at a minimum frequency of 55Hz, and a rotation speed of the blades of 11 revolutions / second.
If the wind turbine is working well under optimum mppt, it must run at a speed in turn / seconds equal to the wind speed Ve in m / s coarsely (with the ratio of 5 approximately, speed at the end of the blade of 5 times the wind speed ) .
It is impossible as soon as there are eddies that change the direction of the wind from 5 to 10 °, as on the video of the scams, because stalls (excessive incidence) or braking (negative impact).
To set, the optimum point mmpt is the one where the current I is believed to be the square of the optimum voltage U, which gives the obtained power P = UxI = U ^ 3 increasing as the cube of that Ve of the wind (Betz constant%) with I = ctxVe ^ 2 U = CtvVe
This U must be decreased by RxI of the voltage lost in the coils, which cuts high voltage, to properly evaluate.
So the 24V ends up at 11m / s of wind stable at U 60 at 70V, Imax 10 at 12A, and the 4 points approaching the curve in I = ct U ^ 2 roughly with straight segments, the first 2 zero to be able to start unloaded blades unhooked at low speed by compared to that of the wind.
So at half voltage 35V I can be Imax / '4 is 2,5A can be less
and at Imax / rac (2) Imax / 2 is 50V about 5 to 6A
This is valid for a place without whirlwinds at all, more than 10 times the height of the different disturbances, and if it is impossible, as for the ransacked, the value will be much lower, the blades remaining constantly unhooked at slow speed and yield divided by 5 at least.
Then the blades are totally unsuitable, too often unhooked.
It is good to measure the frequency of the alternator current (or that of the blades) with oscilloscope or multimeter, as well as the voltages and current, which gives internal R exact, to refine these rough estimates from partial measurements on the German site, charging on variable resistance of power or battery (a simple heater of contactor can do the case of resistance).
The fluctuation of the frequency gives a clear indication on the wind vortices.
Hermann's values seem to me inconsistent with those of the Black 600 48V model ???????????????
by comparing to other info on this forum !!
It will never happen to 600W.
It must be the reduction of U by RI intenren in the coils.
Edit: Hermann am 4.10.09 Wie sich jetzt herausstellt ist mein Black 600 nicht wie jeder andere 600er, deshalb ist es fraglich ob diese Einstellung
also für andere 600er gut ist.Bitte weiterlesen.
Vielleicht kann Generator un mal sagen bei welcher Umdrehung der 600er48V die 28,5 Volt erzeugt.
Das sind auf jeden Fall nur wenige Umdrehungen.
Die Einstellung 27 V für den unteren Punkt würde ich persönlich nicht wählen, Weil dies die eigentliche Abschaltspannung ist, dh bei deiner Einstellung fallen Ein- und Ausschaltpunkt zusammen, lässt ihm keinen Puffer.
Die max. Leistung wirst of the nicht erreichen, weil dein Black bei der von gewählten Spannung noch nicht die erforderliche Leistung hat.
Vielleicht kann Generator a bad sagen bei welcher Umdrehung der 600er48V die 28,5 Volt erzeugt.
Logically the 48V rises more than twice as the 12V, to manage to charge the battery of 48V (or 12V respectively), but the internal resistance R (to measure !!) decreases in appearance U of RI, high voltage, this which is to be evaluated, probably more than 300W of lost in the coils for a high internal resistance.
On the forum we find a lot of inconsistencies!
Understanding by measuring characteristics carefully avoids mistakes.